Re: MD5 Folding in kernel RNG

Previous message: [thread] [date] [author]
Next message: [thread] [date] [author]
From: Ted Unangst
Date: Monday, December 27, 2010 - 9:02 pm

On Mon, Dec 27, 2010 at 8:07 PM, Kjell Wooding <kjell@openbsd.org> wrote:

First thought would be, in the event that there's a bias in MD5 (bit
12 is set 75% of the time), it would "help"?  No, it doesn't.

Maybe if output bit 12 is always the same as input bit 12 and we want
to avoid revealing the input?  That would work, assuming the xor bit
is random.

Despite its flaws, MD5 doesn't have any biases I'm aware of and should
have an even distribution of bits, so the fold neither adds anything
nor takes any more away (other than the obvious cut half).
Previous message: [thread] [date] [author]
Next message: [thread] [date] [author]

Messages in current thread:
MD5 Folding in kernel RNG, Kjell Wooding, (Mon Dec 27, 6:07 pm)
Re: MD5 Folding in kernel RNG, Ted Unangst, (Mon Dec 27, 9:02 pm)
Re: MD5 Folding in kernel RNG, Damien Miller, (Tue Dec 28, 1:48 am)
Re: MD5 Folding in kernel RNG, Kjell Wooding, (Tue Dec 28, 1:08 pm)
Re: MD5 Folding in kernel RNG, Damien Miller, (Tue Dec 28, 1:45 pm)
Re: MD5 Folding in kernel RNG, Kjell Wooding, (Tue Dec 28, 2:42 pm)