On Wed, 2009-03-04 at 01:39 -0800, David Miller wrote:
quoted text
> From: "Zhang, Yanmin" <yanmin_zhang@linux.intel.com>
> Date: Wed, 04 Mar 2009 17:27:48 +0800
> 
> > Both the new skb_record_rx_queue and current kernel have an
> > assumption on multi-queue. The assumption is it's best to send out
> > packets from the TX of the same number of queue like the one of RX
> > if the receved packets are related to the out packets. Or more
> > direct speaking is we need send packets on the same cpu on which we
> > receive them. The start point is that could reduce skb and data
> > cache miss.
> 
> We have to use the same TX queue for all packets for the same
> connection flow (same src/dst IP address and ports) otherwise
> we introduce reordering.
> Herbert brought this up, now I have explicitly brought this up,
> and you cannot ignore this issue.
Thanks. Stephen Hemminger brought it up and explained what reorder
is. I answered in a reply (sorry for not clear) that mostly we need spread
packets among RX/TX in a 1:1 mapping or N:1 mapping. For example, all packets
received from RX 8 will be spreaded to TX 0 always.


quoted text
> 
> You must not knowingly reorder packets, and using different TX
> queues for packets within the same flow does that.
Thanks for you rexplanation which is really consistent with Stephen's speaking.


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