Hi,

2008/8/5 Luis R. Rodriguez <lrodriguez@atheros.com>:
quoted text
> +static inline void __list_cut_position(struct list_head *list,
> +               struct list_head *head, struct list_head *entry)
> +{
> +       struct list_head *new_first =
> +               (entry->next != head) ? entry->next : head;

Isn't this just an over-complicated way of writing "new_first = entry->next"?

quoted text
> +       list->next = head->next;
> +       list->next->prev = list;
> +       list->prev = entry;
> +       entry->next = list;
> +       head->next = new_first;
> +       new_first->prev = head;
> +}
> +
> +/**
> + * list_cut_position - cut a list into two
> + * @list: a new list to add all removed entries
> + * @head: a list with entries
> + * @entry: an entry within head, could be the head itself
> + *     and if so we won't cut the list
> + */

I think it would be helpful if the comment explained what the function
actually does, i.e. that it moves the inital part of 'head' (up to and
including 'entry' from 'head' to 'list'.

quoted text
> +static inline void list_cut_position(struct list_head *list,
> +               struct list_head *head, struct list_head *entry)
> +{
> +       BUG_ON(list_empty(head));
> +       if (list_is_singular(head))
> +               BUG_ON(head->next != entry && head != entry);

No other list function in "list.h" has BUG_ONs.  Why this one?

quoted text
> +       if (entry == head)
> +               INIT_LIST_HEAD(list);

If there was data in 'list' before the call, it will be lost now.  Is
this intended behaviour?

quoted text
> +       else
> +               __list_cut_position(list, head, entry);
> +}
> +

I hope this helps,
Jochen
-- 
http://seehuhn.de/
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