Le mercredi 27 octobre 2010 à 15:42 +0200, Tejun Heo a écrit :
quoted text
> Hello,
> 
> On 10/27/2010 03:33 PM, Eric Dumazet wrote:
> > Le mercredi 27 octobre 2010 à 11:57 +0200, Peter Zijlstra a écrit :
> >> On Wed, 2010-10-27 at 08:07 +0200, Eric Dumazet wrote:
> >>>> -     irqctx = &per_cpu(hardirq_stack, cpu);
> >>>> +     irqctx = (union irq_ctx *)__get_free_pages(THREAD_FLAGS, THREAD_ORDER);
> >>>
> >>> Hmm, then we lose NUMA affinity for stacks. 
> >>
> >> I guess we could use:
> >>
> >>   alloc_pages_node(cpu_to_node(cpu), THREAD_FLAGS, THREAD_ORDER);
> >>
> >>
> > 
> > Anyway, I just discovered per_cpu data on my machine (NUMA capable) all
> > sit on a single node, if 32bit kernel used.
> > 
> > # cat /proc/buddyinfo 
> > Node 0, zone      DMA      0      1      0      1      2      1      1      0      1      1      3 
> > Node 0, zone   Normal     94    251     81     16      3      2      1      2      1      2    187 
> > Node 0, zone  HighMem    113     88     47     36     18      5      4      3      2      0    268 
> > Node 1, zone  HighMem    154     97     43     16      9      4      3      2      3      2    482 
> ...
> > 
> > I presume node 1 having only HighMem could be the reason ?
> 
> What does cpu_to_node() on each cpu say?  Also, do you know why
> num_possible_cpus() is 32, not 16?
> 

I dont know, machine is HP ProLiant BL460c G6 
[    0.000000] SMP: Allowing 32 CPUs, 16 hotplug CPUs

for_each_possible_cpu(cpu) {
	pr_err("cpu=%d node=%d\n", cpu, cpu_to_node(cpu));
}

cpu=0 node=1
cpu=1 node=0
cpu=2 node=1
cpu=3 node=0
cpu=4 node=1
cpu=5 node=0
cpu=6 node=1
cpu=7 node=0
cpu=8 node=1
cpu=9 node=0
cpu=10 node=1
cpu=11 node=0
cpu=12 node=1
cpu=13 node=0
cpu=14 node=1
cpu=15 node=0
cpu=16 node=0
cpu=17 node=0
cpu=18 node=0
cpu=19 node=0
cpu=20 node=0
cpu=21 node=0
cpu=22 node=0
cpu=23 node=0
cpu=24 node=0
cpu=25 node=0
cpu=26 node=0
cpu=27 node=0
cpu=28 node=0
cpu=29 node=0
cpu=30 node=0
cpu=31 node=0




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