Pekka J Enberg wrote:Hmm. double kfree() should be cached by the redzone code. And I disagree with your link interpretation: 000: 00 e0 12 f2 88 32 c0 f7 88 00 00 00 88 50 90 f2 010: inuse: 14 00 00 00 (20 entries in use, 6 should be free) free: 0f 00 00 00 nodeid: 00 00 00 00 bufctl[0x00] ff ff ff ff 020: fd ff ff ff fd ff ff ff fd ff ff ff bufctl[0x4] fd ff ff ff 030: fd ff ff ff fd ff ff ff fd ff ff ff bufctl[0x8] fd ff ff ff 040: fd ff ff ff fd ff ff ff 00 00 00 00 bufctl[0x0c] fd ff ff ff 050: fd ff ff ff fd ff ff ff 19 00 00 00 bufctl[0x10] 17 00 00 00 060: fd ff ff ff fd ff ff ff 0b 00 00 00 bufctl[0x14] fd ff ff ff 070: fd ff ff ff fd ff ff ff fd ff ff ff bufctl[0x18] fd ff ff ff 080: 10 00 00 00 free: points to entry 0x0f. bufctl[0x0f] is 0x19, i.e. it points to entry 0x19 0x19 points to 0x10 0x10 points to 0x17 0x17 is a BUFCTL_ACTIVE - that's a bug. but: 0x13 is a valid link entry, is points to 0x0b 0x0b points to 0x00, which is BUFCTL_END. IMHO the most probable bug is a single bit error: bufctl[0x10] should be 0x13 instead of 0x17. What about printing all redzone words? That would allow us to validate the bufctl chain. Andrew: Could you post the new oops? -- Manfred --
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