On Thu, May 01, 2008 at 04:21:16PM -0700, Tom Rini wrote:
Other thing we observed was: this does not just depend on the __weak
function definition. It also depends on where the function is called from.
__weak function with single return statement, did not get inlined when called
from say
caller()
{
function();
}
but got inlined when called as in
caller()
{
for (;;) {
function();
}
}
Thanks,
Venki
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