Re: [linux-pm] [RFC][PATCH 0/2 -mm] kexec based hibernation -v3

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To: Huang, Ying <ying.huang@...>
Cc: Eric W. Biederman <ebiederm@...>, Pavel Machek <pavel@...>, <nigel@...>, Andrew Morton <akpm@...>, Jeremy Maitin-Shepard <jbms@...>, <linux-pm@...>, Kexec Mailing List <kexec@...>, <linux-kernel@...>
Date: Friday, September 21, 2007 - 5:47 am

> Usage:
Here we save also kernel B's pages.
0-640K from kernel A overrides 0-640K of kernel C at restore time.
This steps replaces kernel C's pages with kernel B's (at least 15m-16m), 
saved at step 8, so these kernels should be equal? Or they must be 
physically located in non-overlapping regions such that C is in B's 
memory range but non-overlapping. The proposed setup doesn't guaratee 
this afaics.
--Mika


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Messages in current thread:
[RFC][PATCH 0/2 -mm] kexec based hibernation -v3, Huang, Ying, (Thu Sep 20, 1:34 am)
Re: [linux-pm] [RFC][PATCH 0/2 -mm] kexec based hibernation ..., Mika Penttilä, (Fri Sep 21, 5:47 am)