On Wed, 08 Aug 2007 17:08:44 -0400
Chris Snook <csnook@redhat.com> wrote:

quoted text
> Heiko Carstens wrote:
> > On Wed, Aug 08, 2007 at 03:21:31AM -0700, David Miller wrote:
> >> From: Heiko Carstens <heiko.carstens@de.ibm.com>
> >> Date: Wed, 8 Aug 2007 11:33:00 +0200
> >>
> >>> Just saw this while grepping for atomic_reads in a while loops.
> >>> Maybe we should re-add the volatile to atomic_t. Not sure.
> >> I think whatever the choice, it should be done consistently
> >> on every architecture.
> >>
> >> It's just asking for trouble if your arch does it differently from
> >> every other.
> > 
> > Well..currently it's i386/x86_64 and s390 which have no volatile
> > in atomic_t. And yes, of course I agree it should be consistent
> > across all architectures. But it isn't.
> 
> Based on recent discussion, it's pretty clear that there's a lot of 
> confusion about this.  A lot of people (myself included, until I thought 
> about it long and hard) will reasonably assume that calling 
> atomic_read() will actually read the value from memory.  Leaving out the 
> volatile declaration seems like a pessimization to me.  If you force 
> people to use barrier() everywhere they're working with atomic_t, it 
> will force re-reads of all the non-atomic data in use as well, which 
> will cause more memory fetches of things that generally don't need 
> barrier().  That and it's a bug waiting to happen.
> 
> Andi -- your thoughts on the matter?

I'm not Andi, but this not-Andi thinks that permitting the compiler to cache
the results of atomic_read() is dumb.

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