Anton Altaparmakov wrote:

quoted text
>> ---LSB-- ---2SB-- ---3SB-- ---MSB-- [bytes] LITTLE_ENDIAN
>> L234567M L234567M L234567M L234567M  [bits] LITTLE_ENDIAN_BITFIELD
> 
> No it is not.  That makes no sense. 

Why not?  I honestly don't know what x86 does, but I would think that if I 
write a 32-bit value to a memory location, that when I examine that memory 
location, all 32 bits will be in order.

quoted text
> The whole point of little endian is 
> that you store LSB, then 2SB, then 3SB, then MSB and then when the CPU 

You're talking about byte endian.  I'm talking about bit endian -- the order 
of bits within a byte.  Software cannot know what the bit endian is, but 
external devices that have memory-mapped registers can know.

quoted text
> reads this as a 32-bit word it rotates them all around so that in the 
> CPU register you have:
> 
> MSB_3SB_2SB_LSB
> M765432L_M765432L_M765432L_M765432L
> 
> That is what little endian means and that is how shift operations can 
> work fine on the CPU.

The CPU shift operation, yes.  I'm talking about shift operations on external 
memory-mapped devices.

-- 
Timur Tabi
Linux Kernel Developer @ Freescale
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